8x=4(x^2+2x)

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Solution for 8x=4(x^2+2x) equation: 



8x=4(x^2+2x)

We move all terms to the left:

8x-(4(x^2+2x))=0



We calculate terms in parentheses: -(4(x^2+2x)), so:

4(x^2+2x)

We multiply parentheses

4x^2+8x

Back to the equation:

-(4x^2+8x)



We get rid of parentheses

-4x^2+8x-8x=0

We add all the numbers together, and all the variables

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$

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